Python email by smtplib and MIMEMultipart example
"""The first step is to create an SMTP object, each object is used for connection
with one server."""
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
server = smtplib.SMTP('smtp.goyun.info', 587)
#debug
server.set_debuglevel(1)
# or server.set_debuglevel(True) # show communication with the server
#TLS
server.starttls()
#Next, log in to the server
server.login("user-name", "password")
me="sender@goyun.info"
you="recipient@goyun.info"
#Send the mail
msg = MIMEMultipart('alternative')
msg['Subject'] = "Test example"
msg['From'] = me
msg['To'] = you
html = '<html><body><p>Hi, I have the following contents for you!</p></body></html>'
part2 = MIMEText(html, 'html')
# or part2=MIMEText(text, 'plain')
msg.attach(part2)
server.sendmail(me, you, msg.as_string())
server.quit()
The following is taken from http://rosettacode.org/wiki/Send_an_email#Python
The function returns a dict of any addresses it could not forward to; other connection problems raise errors.
Tested on Windows, it should work on all POSIX platforms.
Tested on Windows, it should work on all POSIX platforms.
import smtplib
def sendemail(from_addr, to_addr_list, cc_addr_list,
subject, message,
login, password,
smtpserver='smtp.gmail.com:587'):
header = 'From: %s\n' % from_addr
header += 'To: %s\n' % ','.join(to_addr_list)
header += 'Cc: %s\n' % ','.join(cc_addr_list)
header += 'Subject: %s\n\n' % subject
message = header + message
server = smtplib.SMTP(smtpserver)
server.starttls()
server.login(login,password)
problems = server.sendmail(from_addr, to_addr_list, message)
server.quit()
return problems
Example use:
sendemail(from_addr = 'python@RC.net',
to_addr_list = ['RC@gmail.com'],
cc_addr_list = ['RC@xx.co.uk'],
subject = 'Howdy',
message = 'Howdy from a python function',
login = 'pythonuser',
password = 'XXXXX')
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